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Q.

Maximum value of $\sin x . \cos x$ is attained at $x =$

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a

$π$

b

$\frac{π}{2}$

c

$\frac{π}{3}$

d

$\frac{π}{4}$

answer is D.

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Detailed Solution

$\sin x . \cos x = \frac{1}{2} \sin 2 x$

maximum value obtained if $\sin 2 x = 1$

$\Rightarrow 2 x = \frac{π}{2}$ $\Rightarrow x = \frac{π}{4}$

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