Mean lives of a radioactive substance are 1620 years and 405 year for $α -$ emission and $β -$ emission respectively. If a sample of the substance decays by emitting both $α$ and $β$ emission simultaneously, then the time (in years) in which $\frac{3}{4} t h$ sample will decay is
(take, $\log_{e}^{} 2 = 0.693$ and Round-off the answer to two decimal places)

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answer is 449.06.

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Detailed Solution

$τ = \frac{τ_{1} τ_{2}}{τ_{1} + τ_{2}} = 324 T = \frac{324}{1.443} = 224.53 E = 2 T = 449.06 y e a r s$

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