Mech:
I)
II)
III)
IV)
V)
above mechanism is not correct for some hydrogen halides.
Correct statement among the following is

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Reaction III is one of the reactions in chain propagation

In case of HCl, in the step-IV Question Image is the intermediate corresponding to major product.

In case of HBr, both step-IV and V are exothermic

In case of HI, Step-IV is exothermic but step-V is endothermic

answer is C.

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Detailed Solution

	Step-I $H_{2} C = C H_{2} + X \to_{}^{} C H_{2} - C H_{2} X$	Step-II $C H_{2} - C H_{2} X + H X \to_{}^{} C H_{3} - C H_{2} X + X$
HF	$Δ H = - 188 k J$	$Δ H = + 155 k j$
HCl	$Δ H = - 109 k J$	$Δ H = + 21 k j$
HBr	$Δ H = - 21 k j$	$Δ H = - 46 k J$
HI	$Δ H = + 29 k j$	$Δ H = - 133 k J$

Addition of HCl in the presence of peroxide is electrophilic addition mechanism and the intermediate corresponding to major product is ${(C H_{3})}_{2} \overset{\oplus}{C} H$

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