Melting point of any solid depends on pressure as 

$\left(P_2-P_1\right)=\frac{\mathrm{\Delta }{H}_{\text{fusion }}}{V_1-V_S}\cdot \ln \frac{T_2}{T_1}$
Calculate freezing point of water (in $\mathrm{C}°$ ) at a pressure of 1001 bar if freezing point of water at 1 bar is $0°\mathrm{C}$. Molar volume of ice and liquid water is 19 mL and 18 mL respectively and increase in enthalpy due to melting is $6600\mathrm{J}/\text{ mole }$.

[In $0.975=-0.025$]

[Instruction : Neglect sign of the temperature, therefore if your answer is $-{8.65}^{\circ }\mathbf{C}$, express answer as 9]