Melting point of hydrides of nitrogen family follows the order

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$P H_{3} < A s H_{3} < S b H_{3} < N H_{3}$

$P H_{3} < A s H_{3} < N H_{3} < S b H_{3}$

$P H_{3} < N H_{3} < A s H_{3} < S b H_{3}$

$N H_{3} < P H_{3} < A s H_{3} < S b H_{3}$

answer is D.

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Detailed Solution

$P H_{3} < A s H_{3} < S b H_{3} < N H_{3}$

Melting point of ammonia is highest because of H-bonding and then SbH₃ followed by AsH₃ and least for PH₃ because of van der waal forces. More is the molecular mass, more is the van der waal forces.

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