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Metal A reduces silica converting itself into B. B absorbs moisture and converts into C. When C is
heated with the reduction product of silica liberates a gas. Then A,B,C and gas are

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$Na, {Na}_{2} O, NaOH, H_{2}$

$Na, {Na}_{2} O_{2}, {Na}_{2} {CO}_{3}, O_{2}$

$Na, {Na}_{2} O, {Na}_{2} {CO}_{3}, {CO}_{2}$

$Na, {Na}_{2} O_{2}, NaOH, H_{2}$

answer is A.

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Detailed Solution

${SiO}_{2} + Na \to Si + {Na}_{2} O \overset{H_{2} O}{\to} NaOH$

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