Metal M + air $\overset{Δ}{⟶} A \overset{H_{2} O}{⟶} B \overset{HCl}{⟶}$ White fumes; Metal M can be :

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Na, K or Mg

Li, Na or K

Li, Mg

Li, Al or K

answer is A.

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Detailed Solution

$Li / Mg + O_{2} & N_{2} \overset{Δ}{⟶} {Li}_{3} N / {Li}_{2} O / {Mg}_{3} N_{2} / MgO \to_{}^{H_{2} O} Li (OH) / Mg (OH)_{2} + {NH}_{3} \overset{HCl}{\to} \underset{White fumes}{{NH}_{4} Cl}$

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