Q.

Methanol is used as a fuel in a fuel cell used for producing electricity from the following reaction CH3OH(l)+32O2( g)CO2( g)+2H2O(l)  calculate the efficiency of conversion of gibbs energy into useful work. From the following data (in percentage) ΔfG0-CO2=-394.36 kJ/mol;H2O=-237.13 kJ/mol  CH3OH=-166.27 kJ/mol;O2=0 kJ/mol Standard enthalpy of combustion of CH3OH is -726 kJ/mol

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answer is 96.7.

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Detailed Solution

ΔfG0 of the reaction =ΔGP0-ΔGR0=-702.35 kJ/mol

Efficiency of conversion of gibbs energy into useful work.

=ΔfG0ΔH0×100=-702.35-726×100=96.7%

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