Mg₂C₃ reacts with water forming propyne gas. $C_{3}^{4 -}$ - ions has :

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two sigma and two pi bonds

three sigma and one pi bond

two sigma and one pi bond

two sigma and three pi bonds

answer is A.

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Detailed Solution

$\underset{(Allylide wbide)}{{Mg}_{2} C_{3}} + 4 H_{2} O ⟶ 2 Mg (OH)_{2} ↓ + \underset{propyne}{C_{3} H_{4}} ↑$
$HC \equiv C - {CH}_{3} ⟶^{⊖} C \equiv C - C^{(3 -}$
$C_{3}^{4 -} has 2 sigma and 2 pi - bonds .$

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