MgCl2 6H2O on heating does not give anhydrous MgCl2 because

When MgCl2⋅6H2O is strongly heated, then it forms MgO.On heating, MgCl2⋅6H2O readily loses 4 molecules of water of crystallization to form MgCl2⋅2H2O.MgCl2⋅6H2O→Δ→∆MgCl2⋅2H2O + 4H2OThe remaining two molecules of water are not removed but react chemically with MgCl2 to form MgO.MgCl2 + 2H2O → MgO + 2HCl + H2O

MgCl2 6H2O on heating does not give anhydrous MgCl2 because

When MgCl2⋅6H2O is strongly heated, then it forms MgO.On heating, MgCl2⋅6H2O readily loses 4 molecules of water of crystallization to form MgCl2⋅2H2O.MgCl2⋅6H2O→Δ→∆MgCl2⋅2H2O + 4H2OThe remaining two molecules of water are not removed but react chemically with MgCl2 to form MgO.MgCl2 + 2H2O → MgO + 2HCl + H2O

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MgCl₂ 6H₂O on heating does not give anhydrous MgCl₂ because

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MgCl₂ decomposes on heating into Mg & Cl₂

MgCl₂ loses only one H₂O molecule

MgCl₂ hydrolysis in the water formed and gives Mg(OH)Cl

MgCl₂ gives Mg(ClO₃)26H₂O

answer is C.

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Detailed Solution

When MgCl₂⋅6H₂O is strongly heated, then it forms MgO.
On heating, MgCl₂⋅6H₂O readily loses 4 molecules of water of crystallization to form MgCl₂⋅2H₂O.
MgCl₂⋅6H₂O→Δ $\overset{∆}{\to}$ MgCl₂⋅2H₂O + 4H₂O
The remaining two molecules of water are not removed but react chemically with MgCl₂ to form MgO.
MgCl₂+ 2H₂O → MgO + 2HCl + H₂O