$Mg {(OH)}_{2}$ in the form of milk of magnesia is used to neutralize excess stomach acid. How many moles of HCl can be neutralized by 1gm of $Mg {(OH)}_{2}$ ?(Molar mass of $Mg {(OH)}_{2} = 58.33)$
$[Mg {(OH)}_{2} + 2 HCl \to {MgCl}_{2} + 2 H_{2} O]$

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0.0171

0.0343

1.25

0.686

answer is B.

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Detailed Solution

$[Mg {(OH)}_{2} + 2 HCl \to {MgCl}_{2} + 2 H_{2} O]$

$58 g Mg {(OH)}_{2} . . . . . . . . 2 Moles HCl$
$1 gr of Mg {(OH)}_{2} . . . . . . . . . . . . X moles of HCl$
$X = \frac{2}{58}$

Number of moles of HCl is neutralized by 1 gr of $Mg {(OH)}_{2} is = 0.0343$

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