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Q.

$M g (O H)_{2}$ in the form of Milk of Magnesia is used to neutralize excess stomach acid. How many moles of stomach acid can be neutralized by 1.00g of $M g (O H)_{2}$ ?

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a

0.0171

b

0.0343

c

1.25

d

0.686

answer is B.

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Detailed Solution

In the given reaction

$\begin{array}{l} {{Mg}_{g} OH)}_{2} + 2 HCl \to {MgCl}_{2} + 2 H_{2} O \\ \frac{1}{58.33} \times 2 = 0.0343 \end{array}$

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