Λm∘H2O is equal to ____

Λ m ( HCl ) ∘ + Λ m ( NaOH ) ∘ − Λ m ( NaCl ) ∘

Λ m ( HCl ) ∘ + Λ m ( NaOH ) ∘ − Λ m ( NaCl ) ∘

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$Λ_{m}^{\circ} H_{2} O$ is equal to ____

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$Λ_{m (HCl)}^{\circ} + Λ_{m (NaOH)}^{\circ} - Λ_{m (NaCl)}^{\circ}$

$Λ_{m ({HNO}_{3})}^{0} + Λ_{m ({NaNO}_{3})}^{0} - Λ_{m (NaOH)}^{0}$

$- Λ_{m ({HNO}_{3})}^{0} - Λ_{m (NaOH)}^{0} - Λ_{m ({NaNO}_{3})}^{0}$

$Λ_{m ({HNO}_{3})}^{0} + Λ_{m (NaOH)}^{0} + Λ_{m ({NaNO}_{3})}^{0}$

answer is A.

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$Λ_{m}^{0} H_{2} O = Λ_{m}^{o} (HCl) + Λ_{m}^{o} (NaOH) - Λ_{NaCl}^{\circ}$

$= Λ_{H^{+}}^{0} + Λ_{{Cl}^{-}}^{0} + Λ_{{Na}^{+}}^{0} + Λ_{{OH}^{-}}^{0} - Λ_{{Na}^{+}}^{0} - Λ_{{Cl}^{-}}^{0}$

$Λ_{m}^{0} (H_{2} O) = Λ_{H^{+}}^{0} + Λ_{{OH}^{-}}^{0}$

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