Mihir was asked to solve the fraction $\frac{\frac{5}{3}+1\frac{1}{2} \mathrm{of} \frac{7}{3}}{2+2\frac{2}{3}}$ and his answer was $\frac{1}{7}$ By how much times was his answer wrong? 

: Consider $\frac{\frac{5}{3}+1\frac{1}{2} \mathrm{of} \frac{7}{3}}{2+2\frac{2}{3}}$
$=\frac{\frac{5}{3}+\frac{3}{2}\times \frac{7}{3}}{2+\frac{8}{3}}=\frac{\frac{5}{3}+\frac{7}{2}}{\frac{2}{1}+\frac{8}{3}}=\frac{\frac{10+21}{6}}{\frac{6+8}{3}}=\frac{31}{6}\times \frac{3}{14}=\frac{31}{28}$
But Mihir answered $=\frac{1}{7}$
His answer is $\left(\frac{31}{28}÷\frac{1}{7}\right)$ times wrong  $=\frac{31}{28}\times 7=\frac{31}{4}$