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Minimum force F required to move a object on horizontal rough surface is_____

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\frac{mg}{2}

\sqrt{3} mg

\frac{mg}{\sqrt{3}}

mg

answer is D.

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Detailed Solution

F_{min} = \frac{μ mg}{\sqrt{1 + μ^{2}}}

$= \frac{\frac{1}{\sqrt{3}} mg}{\frac{2}{\sqrt{3}}} = \frac{mg}{2}$

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