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Mirror in the arrangement shown in figure is moving up with speed 4 cm/sec. Find the speed of final image of object O (in cm/s) formed after two refraction and one reflection

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answer is 6.

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Detailed Solution

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Apparent distance of mirror from O
$= x + \frac{y}{μ}$
Distance of final image from O
$= 2 (x + \frac{y}{μ})$
velocity of image

$= 2 (\frac{d y}{d t} + \frac{1}{μ} \frac{d y}{d t}) = \frac{2}{μ} \times 4 = 6$

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