${MnO}_{2}$ when fused with KOH and oxidised in air gives a dark green compound $X$ .
In acidic solution, $X$ undergoes disproportionation to give an intense purple colour
compound $Y$ and ${MnO}_{2}$ . The compound $X and Y$ respectively, are

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$K_{2} {MnO}_{4} and {KMnO}_{4}$

$K_{2} {MnO}_{4} and {Mn}_{2} O_{7}$

${Mn}_{2} O_{7} and {KMnO}_{4}$

${KMnO}_{4} and K_{2} {MnO}_{4}$

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$2 {MnO}_{2} + 4 KOH + O_{2} \overset{Oxidised in air}{\to} \frac{2 K_{2} {MnO}_{4}}{X [Dark green compound]} + 2 H_{2} O$

$3 \overset{+ 6}{Mn} O_{4}^{- 2} + 4 H^{+} \overset{Disproportionation}{\to} \frac{2 \overset{+ 7}{Mn} O_{4}^{-}}{Y [Purple compound]} + \overset{+ 2}{Mn} O_{2} + 2 H_{2} O$

Watch 3-min video & get full concept clarity

hear from our champions

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!