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$(m, n, p)$ is Pythagorean triplet if $m^{2} + n^{2} = p^{1}$ and given $(m, 12, 13)$ is Pythagorean triplet then $m =$

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answer is 5.

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Detailed Solution

$m^{2} + n^{2} = p^{1}$

$m^{2} + 12^{2} = 13^{2}$

$m^{2} = 169 - 144$

$m^{2} = 25$

$: . m = 5$

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m,n,p is Pythagorean triplet if m2+n2=p1 and given m,12,13 is Pythagorean triplet then m=