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Q.

Mohan gets 3marks for each correct sum and loses 2marks for each wrong sum. He attempts 30 sums and obtains 40marks. The number of sums solved correctly is


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a

10

b

15

c

20

d

25  

answer is C.

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Detailed Solution

It is given Mohan gets 3marks for each correct sum and loses 2marks for each wrong sum and he attempts 30 sums and obtains 40marks.
Let the number of sums solved correctly be n.
Then number of wrong sums =30-n According to question,
3n-2.(30-n)=40 3n-60+2n=40 5n=100 n=20
Therefore, the number of sums solved correctly is 20.
Hence, the correct option is 3.
 
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