Mohit painted the outside of a box of length $2.5 m$ , breadth $2 m$ and height $1 m$ . How much area did he cover, if he painted all except the bottom of the box?

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20 m^{2}

16 m^{2}

54 m^{2}

14 m^{2}

answer is D.

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Detailed Solution

Given that, the dimensions of box are:
Length= 2.5m
Breadth =2m
Height= 1m
Question Image

The formula for the surface area of the cuboid having length, breadth and height as

l, b

and

h

respectively is given as

2 (lb + bh + hl)

.
So, after substituting the value of all the dimensions in the formula we get,
Then the area Mohit painted

\Rightarrow 2 (2.5 \times 2 + 2 \times 1 + 2.5 \times 1) - (2.5 \times 2)

\Rightarrow 2 (5 + 2 + 2.5) - (5)

\Rightarrow 2 (9.5) - 5

\Rightarrow 19 - 5

\Rightarrow 14 m^{2}

Therefore, the area covered is

14 m^{2}

, if he painted all except the bottom of the box.
Hence option (4) is correct.

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