Moist air is less dense than dry air at the same temperature and barometric pressure. Which is the best explanation for this observation?

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$H_{2} O$ is a polar molecule but $N_{2}$ and $O_{2}$ are not.

$H_{2} O$ has a higher boiling point than $N_{2}$ or $O_{2}$

$H_{2} O$ has a lower molar mass than $N_{2}$ or $O_{2}$

$H_{2} O$ has a higher heat capacity than $N_{2}$ or $O_{2}$

answer is C.

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Detailed Solution

When water molecules are added to a volume of air to increase moisture, heavier molecules are swapped out for lighter ones. Therefore, if both types of air are at the same pressure and temperature, wet air will be lighter than dry air.

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