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Molal depression constant for water is 1.86 K.Kg. mole^–1. The freezing point of a 0.05 molal solution of a non electrolyte in water is

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–1.86°C

–0.93°C

–0.093°C

0.93°C

answer is C.

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Detailed Solution

$∆ T_{f} = K_{f} \times m = 1.86 \times 0.05 = 0.093 {}^{0}C$

${ΔT}_{f} = T_{f}^{0} - ∆ T_{f} = 0 {}^{0}C - 0.093 {}^{0}C = - 0.093 {}^{0}C$

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