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Molal depression constant is given by the expression :

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$∆ T_{f} \times m$

$∆ T_{f} \times M$

$∆ T_{f} / M$

$∆ T_{f} / m$

answer is D.

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Detailed Solution

The term "molal depression constant" refers to the decrease in freezing point that results from dissolving one mole of a non-volatile solute in one kilogram, or 1000 g, of the solvent. Additionally called the cryoscopic constant.

K_f=∆T_f/m.

where K_f is molal depression constant.

Hence, the correct option (D).

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