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Molal elevation constant of a liquid is:

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the elevation of b.p. which would be produced by dissolving 1 mole solute in 10 g of solvent

none of the above

the elevation in b.p. which would be produced by dissolving one mole of solute in 100 g of solvent

elevation in b.p. which would be produced by dissolving 1 mole solute in 1000 g of solvent

answer is C.

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Detailed Solution

$\begin{array}{l} {ΔT}_{b} = \frac{1000 K'_{b} \times w}{m . W}; if w / m = 1, \\ W = 1000 g, \\ {ΔT}_{b} = K'_{b} \end{array}$

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