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Molality of 10% $(w / v)$ aqueous solution of NaOH is (Let density of NaOH solution = $1.1 g / cc)$

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2.5 m

3.25 m

6 m

1.75 m

answer is C.

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Detailed Solution

$W_{solute} = 10 g$

$V_{solution} = 100 ml; d_{solution} = 1.1 g / ml$

$W_{solution} = 110 g, W_{solvent} = 100 g$

$m = \frac{10}{40} \times \frac{1000}{100} = 2.5 m$

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