Molar conductance at infinite dilution of Barium chloride, Sodium hydroxide and Sodium chloride are X, Y and Z respectively. Molar conductance at infinite dilution of Barium hydroxide at the same temperature would be (all measurements expressed in SI units)

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X + 2Z - 2Y

-X + 2Y + 2Z

X + Y - Z

X + 2Y - 2Z

answer is B.

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Detailed Solution

According to Kohlrausch law

$\begin{array}{l} Λ_{{BaCl}_{2}}^{m} = {Λ_{{Ba}^{2 +}}^{m}}^{} + 2 Λ_{{Cl}^{-}}^{m} . . . . (1) \\ Λ_{NaOH}^{m} = Λ_{{Na}^{+}}^{m} + Λ_{{OH}^{-}}^{m} . . . . . (2) \\ Λ_{NaCl}^{m} = Λ_{{Na}^{+}}^{m} + Λ_{{Cl}^{-}}^{m} . . . . . (3) \\ Λ_{Ba {(OH)}_{2}}^{m} = Λ_{{Ba}^{2 +}}^{m} + 2 Λ_{{OH}^{-}}^{m} . . . (4) \\ Eq (1) + 2 \times Eq (2) - 2 \times Eq (3) = Eq (4) \\ X + 2 Y - 2 Z = Λ_{Ba {(OH)}_{2}}^{m} \end{array}$

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