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Q.

Molar conductance of 0.01M weak monoprotic acid (HA) is 40 mho cm2 mol-1. pH of the solution is (Limiting molar conductance of HA is 400 mho cm2 mol-1).

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a

2

b

3

c

4

d

2.3

answer is D.

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Detailed Solution

α=40400=0.1[H+]=Cα       =(0.01)(0.1)=10−3   pH=3

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