Molar conductance of 0.1 M acetic acid is $7 {ohm}^{- 1} {cm}^{2} {mol}^{- 1}$ . If the molar conductance of acetic acid at infinite dilution is $380.8 {ohm}^{- 1} {cm}^{2} {mol}^{- 1}$ , the value of dissociation constant will be:

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$1 .66 \times 10^{- 3} mol {dm}^{- 1}$

$226 \times 10^{- 5} {mol dm}^{- 3}$

$3 .38 \times 10^{- 5} mol {dm}^{- 3}$

$1 .66 \times 10^{- 2} mol {dm}^{- 3}$

answer is D.

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Detailed Solution

$K_{a} = {Cα}^{2} = 0 .1 \times {(\frac{7}{380 .8})}^{2} = 3 .38 \times 10^{- 5}$

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