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Molar conductivity of a solution is 1.26 × 10² $Ω^{- 1}$ cm²mol^–1. Its molarity is 0.01M. Its specific conductivity will be

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1.26 × 10^–3

0.0063

1.26 × 10^–4

1.26 × 10^–5

answer is B.

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Detailed Solution

${\lambda _m} = \kappa \times \frac{{1000}}{M}$

$\kappa = \frac{{1.26 \times {{10}^2} \times {{10}^{ - 2}}}}{{1000}} = 1.26 \times {10^{ - 3}}mhoc{m^{ - 1}}$

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