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Q.

Molar conductivity of a solution is 1.26 × 10² $Ω^{- 1} {cm}^{2} {mol}^{- 1}$ Its molarity is 0.01M. Its specific conductivity will be

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a

0.0063

b

1.26 × 10^–3

c

1.26 × 10^–4

d

1.26 × 10^–5

answer is B.

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Detailed Solution

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Molar conductivity ( $\land_{m}$ )

$\land_{m} = \frac{k \times 1000}{M o l a r i t y}$

$1.26 \times 10^{2} = \frac{k \times 1000}{0.01}$

$k = 1.26 \times 10^{- 3}$

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Molar conductivity of a solution is 1.26 × 102 Ω−1cm2mol−1 Its molarity is 0.01M. Its specific conductivity will be