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Q.

Molar conductivity of a solution of an electrolyte AB3 is 150 scm2mol-1. If it ionises as AB3⟶A3++3B−, its equivalent conductivity will be :

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a

150 (in S cm2eq-1)

b

50 (in S cm2eq-1)

c

80 (in S cm2eq-1)

d

75 (in S cm2eq-1)

answer is C.

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Detailed Solution

The relation between Molar and equivalent conductivities  (λeq=1000×KN  ; λμ=1000×KM)

λeqλμ=1n λeq =λμn

∧eq=1503=50Scm2eq−1

 

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