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Q.

Molar conductivity of BaCl2,KCl and KOH is x,y,z mho cm2mole−1 respectively. Equivalent conductance of Ba(OH)2 is 

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a

x+2z−2y2

b

x + z – y

c

2(x+2z–2y)

d

x + 2z – 2y

answer is C.

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Detailed Solution

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λBa(OH)2∞=λBaCl2∞+2λKOH∞-2λKCl∞

For Ba(OH)2 the molar conductivity = x+ 2Z-2Y

Equivalent conductivity = x+2z-2y2

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