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Q.

Molar heat of vapourization for water is 9.72   kcal mol−1 at 373K. The boiling point of water is 373 K the molal elevation constant for water (Kb) is 

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a

5.4Kkgmol−1

b

0.59Kkgmol=1

c

0.51Kkgmol−1

d

9.72Kkgmol−1

answer is A.

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Detailed Solution

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Kb=RT02M1000ΔHV =2×10−3×(373)2×181000×9.72 =0.51Kkgmol−1

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