Molar specific heat at constant pressure C_P is related to internal energy U and absolute temperatue T as C_P is equal to

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$\frac{d U}{d T} + R$

$\frac{d U}{d T}$

$U \times T$

$\frac{U}{T}$

answer is C.

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Detailed Solution

From Mayer’s formula
$\begin{aligned} C_{P} - C_{V} = R \\ C_{P} = C_{V} + R \end{aligned}$
At const volume $C_{V} = \frac{d Q}{d T} = \frac{d U}{d T}$
$∴ C_{P} = \frac{d U}{d T} + R$

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