Molar standard enthalpy of combustion of ethanol is $- 1320 kJ$ ,molar standard enthalpy of formation of water and ${CO}_{2} (g)$ are $- 286 kJ / mole$ mole and $- 393 kJ$ mole respectively. Calculate the magnitude of molar standard enthalpy of formation of ethanol.

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answer is 324.

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Detailed Solution

In the reaction we have,

$\begin{array}{l} C_{2} H_{5} OH + 3 O_{2} ⟶ 2 {CO}_{2} + 3 H_{2} C \\ - 1320 = - 2 \times 393 - 3 \times 286 - x \\ \Rightarrow x = - 324 \end{array}$

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