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Molarity and molality of a solution of caustic soda are respectively 11.12 M and 94.12 m. The density of the solution is

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none of these

$5 .63 g {mL}^{- 1}$

$56 .3 g {mL}^{- 1}$

$0 .563 g {mL}^{- 1}$

answer is A.

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Detailed Solution

$d = M [\frac{1}{m} + \frac{molar mass of solute}{1000}]$

$d = 11 .12 (\frac{1}{94 .12} + \frac{40}{1000})$

$d = 0 .563 g {mL}^{- 1}$

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