Molarity equation of a mixture of solutions of same substance is given by

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$M_{1} + V_{1} \times M_{2} + V_{2} \times M_{3} + V_{3} + \dots = M_{1} + M_{2} + M_{3}$

$M_{1} V_{1} + M_{2} V_{2} + M_{3} V_{3} + \dots = M (V_{1} + V_{2} + V_{3})$

$\frac{M_{1}}{V_{1}} + \frac{M_{2}}{V_{2}} + \frac{M_{3}}{V_{3}} + \dots = M (\frac{1}{V_{1}} + \frac{1}{V_{2}} + \frac{1}{V_{3}})$

$\frac{M_{1}}{V_{1}} \times \frac{M_{2}}{V_{2}} \times \frac{M_{3}}{V_{3}} \times = M_{1} (\frac{1}{V_{1}} \times \frac{1}{V_{2}} \times \frac{1}{V_{3}})$

answer is B.

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Detailed Solution

Molarity of a mixture of solution of same substance is given by

$\underset{1st solution}{M_{1} V_{1}} + \underset{2nd solution}{M_{2} V_{2}} + \underset{3rd solution}{M_{3} V_{3}} = \dots + M \underset{Mixture}{(V_{1} + V_{2} + V_{3}})$