Molarity of 1m aqueous NaOH solution [density of the solution is 1.02 g/ml]
 

Given data: It is given to identify that molarity of 1m aqueous NaOH solution [density of the solution is 1.02 g/ml]

The relation between molarity and molality is given by -
$M= \frac{1000\times \mathrm{d}}{\left[\right(1000/\mathrm{m})+\mathrm{M}\text{'}]}$
where, 
M is molarity
m is molality
d is density of the solution
M' is the molecular weight of solute
substituting values in this formula,
$M=\frac{1000\times 1.02}{\left[\right(1000/1)+40]}=1020/1040 =0.98$
Hence option(D) 0.98 is correct.