Molarity of the liquid HCl if the density of the solution is 1.17 g/cc is

Density of solution$=1.17 \mathrm{g}/\mathrm{ml}$

We know that $1\mathrm{g}/\mathrm{cc}=1\mathrm{g}/\mathrm{ml}$

The Molar mass of $\mathrm{HCl}=36.5$

We know that Molarity$=\frac{\mathrm{No}. \mathrm{of} \mathrm{moles} \mathrm{of} \mathrm{solute}}{\mathrm{Volume} \mathrm{of} \mathrm{Solution}(\mathrm{in} \mathrm{litres})}$

Also, Molarity can also be $=\frac{\mathrm{Density} \mathrm{in} \mathrm{g}/\mathrm{l}}{\mathrm{molecular} \mathrm{weight}}$

Hence, the Molarity of $\mathrm{HCl}=\frac{1.17\times 1000}{36.5}=\frac{1170}{36.5} \mathrm{M}=32.05 \mathrm{M}$

Therefore, option (c) is correct.