$Molarity of H_{2} {SO}_{4} is 18 M . Its density is 1.8 g / mL . Hence molality is$

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200

500

answer is C.

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Detailed Solution

$Molality (m)$ $= \frac{Molarity}{Density - \frac{Molarity \times Molecular mass}{1000}}$
$= \frac{18}{1 .8 - \frac{18 \times 98}{1000}} = 500 mol {kg}^{- 1}$

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