Mole fraction of glycine molecule in 0.140 molal aqueous solution is

Moles of glycine = 0.140

moles of $H_{2}O=\frac{1000}{18}=55.56$

Total  $=0.14+55.56=55.70$

${\mathrm{X}}_{\mathrm{glycine}}=\frac{\mathrm{n}\left(\mathrm{glycine}\right)}{\mathrm{n}\left(\mathrm{Total}\right)}=\frac{0.14}{55.70}=2.51\times {10}^{-3}$