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Q.

Mole fraction of $I_{2}$ in benzene is 0.2. Find the molality of the solution [Round off the answer to the nearest integer value]

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answer is 3.

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Detailed Solution

$X_{I_{2}} = 0.2; X_{C_{6} H_{6}} = 0.8$

0.8 moles of $C_{6} H_{6}$ contains 0.2 moles of n $I_{2}$

$(0.8 \times 78 g m s) m = \frac{0.2 \times 1000}{0.8 \times 78} = \frac{250}{78} = 3.2$

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