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Mole ratio of Fe in $FeO, {Fe}_{2} O_{3}$ and $F e_{3} O_{4}$ samples of equal masses is

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$1 : 2 : 3$

$3 : 2 : 1$

$0.9 : 1 : 0.93$

$1 : 0.9 : 0.93$

answer is C.

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Detailed Solution

if W gm of Fe is present in all the three compounds then its mole ratio can be obtained as $\frac{W}{72} : \frac{2 W}{160} : \frac{3 W}{232}$ =1 : 0.9 : 0.93

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