Molecular formula of ‘A’ C₈H₈O . ‘A’ gives ppt with 2, 4 DNP. ‘A’ gives yellow crystals with NaOH+I₂ . ‘A’ does not gives Tollen's (or) Fehling test. It neither ‘decolourise Br₂ / H₂O nor Baeyer’s reagent. On oxidation with chromic acid 'A' gives C₇H₆O₂. A & B are

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$C_{6} H_{5} {CH}_{2} CHO, C_{6} H_{5} COOH$

$C_{6} H_{5} {COCH}_{3}, C_{6} H_{5} COOH$

$C_{6} H_{5} {CH}_{2} CHO, {HCOOC}_{6} H_{5}$

$C_{6} H_{5} {COC}_{3}, {HCOOC}_{6} H_{5}$

answer is B.

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Detailed Solution

	2, 4 - DNP	NaOH + I₂	Tollen's	Fehling's	Beayer's
A	Positive	Positive	Negative	negative	Negative

So ‘A’ must be a saturated ketone containing -COCH₃ group.

The M.F suits C₆H₅ - CO - CH₃ , Acetophenone ;

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