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Q.

Molecule AB has a bond length of 1.617A° and a dipole moment of 0.38 D. The fractional charge on each atom (absolute magnitude) is (e0= 4.802 × 10–10 esu)

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a

0

b

0.05

c

1.0

d

0.5

answer is B.

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Detailed Solution

detailed_solution_thumbnail

Dipole moment (μ)=q×d
μ=0.38D (given) = 0.38×10 −18esu cm

Charge, q=μd=0.38×10-181.617×10-8 Fractional charge=0.38×10-181.617×10-8×4.802×10-10=0.048=0.05

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