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Q.

Moles of urea to be dissolved in 12 moles of water to lower its vapour pressure by 10mm Hg at a temperature at which the vapour pressure of pure water is 50mm is

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a

3 mol  

b

1 mol

c

2 mol

d

0.5 mol

answer is A.

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Detailed Solution

ΔPP0=n2n2+n1

1050=n2n2+12

1050=n2n2+12n2=3

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