Q.

Moment of Inertia (M.I.) of four bodies having same mass ‘M’ and radius ‘2R’ are as follows:
I1= M.I. of solid sphere about its diameter
I2 = M.I. of solid cylinder about its axis
I3 = M.I. of solid circular disc about its diameter
I4 = M.I. of thin circular ring about its diameter
If 2(I2 + I3) + I4 = x. I1 then the value of x will be _________ .

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answer is 5.

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Detailed Solution

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 I1=25M(2R)2=85MR2 I2=12M(2R)2=2MR2 I3=M(2R)24=MR2 I4=M(2R)22=2MR2 2(I2+I3)+I4=xI1 8MR2=x85MR2 x=5

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