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Q.

Moment of inertia of a solid cylinder of mass m, length l, radius r about an axis passing through its centre and perpendicular to its length is

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a

$\frac{m l^{2}}{12}$

b

$\frac{m l^{2}}{3}$

c

$\frac{m l^{2}}{12} + \frac{{mr}^{2}}{4}$

d

$\frac{m l^{2}}{12} + \frac{{mr}^{2}}{3}$

answer is C.

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Detailed Solution

Moment of inertia of uniform solid cylinder is equal to $\frac{m l^{2}}{12} + \frac{{mr}^{2}}{4}$

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Moment of inertia of a solid cylinder of mass m, length l, radius r about an axis passing through its centre and perpendicular to its length is