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Q.

Monochromatic light of wavelength 500 nm is incident on two parallel slits separated by a distance of 5×10-4 m. The interference pattern is obtained on a screen at a distance of 1.0 m from the slits. The intensity of the central maximum is I0. When one of the slits is covered by a glass sheet of thickness 5×10-6 m and refractive index 1.5, the lateral shift of the central maximum is …….mm.

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answer is 5.

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Detailed Solution

The lateral shift is given by
Δy=(μ-1)tDd

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