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Q.

Moving with a uniform acceleration from the state of rest a body covers 22m during the 6th sec of its motion. What is the distance covered (in m) by if during the first 6 sec?

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answer is 72.

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Detailed Solution

starting from rest distance travel in the nth sec to n sec have an ratio

$\frac{2 n - 1}{n^{2}} = \frac{22}{s}$

$here n = 6 \frac{11}{6^{2}} = \frac{22}{s} s = 72 m$

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Moving with a uniform acceleration from the state of rest a body covers 22m during the 6th sec of its motion. What is the distance covered (in m) by if during the first 6 sec?